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【关于字体格式】 设置的是第一个字符的颜色,这时richtextBox的rtf中记录下位置0的颜色,重置text时,在rtf中的位置从位置0开始,因此颜色还是Color.Red,第三次也应该同样如此 richTextBox1.Text = "123"; richTextBox1.Select(0, 1); richTextBox1.SelectionColor = Color.Red; richTextBox1.Clear();//清除文本,包括样式 //或richTextBox1.Text=""; richTextBox1.Text = "abc"; richTextBox1.Text = "efg"; 这样重置后的文本颜色就会是黑色. 【关键字着色】 public partial class RichTextBox : Form
 ...{
public RichTextBox()
 ...{
InitializeComponent();
}

private void tSql_TextChanged(object sender, EventArgs e) //文本框改变事件
 ...{
int index = this.tSql.SelectionStart; //记录修改的位置
this.tSql.SelectAll();
this.tSql.SelectionColor = Color.Black;


 string[] keystr =...{ "select ", "from ", "where ", " and ", " or ", " order ", " by ", " desc ", " when ", " case ", " then ", " end ", " on ", " in ", " is ", " else ", " left ", " join ", " not ", " null " };
for (int i = 0; i < keystr.Length; i++)
this.getbunch(keystr[i], this.tSql.Text);

this.tSql.Select(index, 0); //返回修改的位置
this.tSql.SelectionColor = Color.Black;

}
public int getbunch(string p, string s) //给关键字上色
 ...{
int cnt = 0; int M = p.Length; int N = s.Length;
char[] ss = s.ToCharArray(), pp = p.ToCharArray();
if (M > N) return 0;
for (int i = 0; i < N - M + 1; i++)
 ...{
int j;
for (j = 0; j < M; j++)
 ...{
if (ss[i + j] != pp[j]) break;
}
if (j == p.Length)
 ...{
this.tSql.Select(i, p.Length);
this.tSql.SelectionColor = Color.Blue;
cnt++;
}
}
return cnt;

}

}
 【绘制颜色提议】 最好的做法是继承RichTextBox,重载新类的Paint方法。
并且在设置SelectionLength的时候,禁止控件的重绘过程,这样才不会出现被语法高亮的文本有一个突然选中的过程。
以下2个方法将会对你解决这一问题有很大的帮助. [DllImport("user32")] private static extern int SendMessage(IntPtr hwnd, int wMsg, int wParam, IntPtr lParam); private const int WM_SETREDRAW = 0xB;
//停止控件的重绘 private void BeginPaint() { SendMessage(yourRichTextBox.Handle, WM_SETREDRAW, 0, IntPtr.Zero); }
//允许控件重绘. private void EndPaint() { SendMessage(yourRichTextBox.Handle, WM_SETREDRAW, 1, IntPtr.Zero); yourRichTextBox.Refresh(); }
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